Q. A $4_{\mu}$ F conductor is charged to 400 V and then its plates are joined through a resistance of 1 k$\Omega$. The heat produced in the resistance is
A) 0.18 J
B) 0.21 J
C) 0.25 J
D) 0.32 J
Explanation
(d) The energy stored in the capacitor $= \frac{1}{2}CV^{2};$
This energy will be converted into heat in the resistor.
$\ \ H = \frac{1}{2} \times 4 \times 10^{- 6} \times 400 \times 400$
$\ = 32 \times 10^{- 2}$
$\ = 0.32$ J
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.