Q. A coil of wire of resistance 50 $\Omega$ is embedded in a block of ice and a potential difference of 210 V is applied across it. The amount of ice which melts in 1 sec is
A) 0.262 g
B) 2.62 g
C) 26.2 g
D) 0.0262 g
Explanation
(b) Heat produced $= \frac{V^{2}t}{4.2\ R} = mL$
or $m = \frac{V^{2}}{4.2\ R\ L} = \frac{(210)^{2} \times 1}{4.2 \times 50 \times 80} = 2.62\ $g
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.