Q.
In the given circuit diagram the current through the battery and the charge on the capacitor respectively in steady state are
A) $1A$ and $3\ \mu C$
B) $17\ A$ and $0\ \mu C$
C) $\frac{6}{7}A$ and $\frac{12}{7}\mu C$
D) $11A$ and $3\mu C$
Explanation
(d) In steady state capacitor is fully charged and no current flows through it
[image:3_image140.emf]
$\therefore$ No current passes through $4\Omega$
$\frac{1}{R_{eff}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3}$
$= \frac{6 + 3 + 2}{6} = \frac{11}{6}$
$\Rightarrow R_{eff} = \frac{6}{11}\Omega$
Current $= \frac{6 \times 11}{6} = 11A$
$Q = CV = 0.5 \times 10^{- 6} \times 6 = 3.0 \times 10^{- 6}C = 3\mu C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.