Q.
A galvanometer of resistance 20$\ \Omega$ shows a deflection of 10 divisions when a current of 1 mA is passed through it. If a shunt of 4$\ \Omega$is connected and there are 50 divisions on the scale, the range of the galvanometer is
A) 1A
B) 3A
C) 10mA
D) 30mA
Explanation
(d) Current for 50 divisions,
$I_{g} = \frac{1 \times 50}{10} = 2mA$
$\therefore\ \frac{I_{g}}{I} = \frac{S}{S + G\ }$
$\Longrightarrow I = \left( \frac{S + G}{S} \right)I_{g}$
Or
$I = \left( \frac{4 + 20}{4} \right)5mA = 30mA$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.