Q. In a $Ag$ voltameter $2.68\ g$ of silver is deposited in $10\ min.$ The heat developed in $20\Omega$ resistor during the same period will be
A) $192\ kJ$
B) $192\ J$
C) $200\ J$
D) $132\ kJ$
Explanation
(a) $I = \frac{m}{Zt} = \frac{2.68}{\frac{108}{96500} \times 10 \times 60} = \frac{2.68}{108} \times \frac{965}{6} \approx 4\ A$
Energy $= I^{2}Rt = 4^{2} \times 20 \times 600 = 192\ kJ$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.