Q. In producing chlorine through electrolysis $100\ watt$ power at $125\ V$ is being consumed. How much chlorine per minute is liberated? E.C.E. chlorine is $0.367 \times 10^{- 6}kg/coulomb$
A) $24.3\ mg$
B) $16.6\ mg$
C) $17.6\ mg$
D) $21.3\ mg$
Explanation
(c) $P = 100\ watt,\ V = 125\ V$
Since $P = VI,\ \therefore I = \frac{P}{V} = \frac{100}{125}ampere$
Mass of chlorine liberated $= zIt$
$= 0.367 \times 10^{- 6} \times \frac{100}{125} \times 60 = 0.0176 \times 10^{- 3}kg = 17.6mg$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.