Q. The two ends of a uniform conductor are joined to a cell of e.m.f. $E$ and some internal resistance. Starting from the midpoint $P$ of the conductor, we move in the direction of current and return to $P.$ The potential $V$ at every point on the path is plotted against the distance covered $(x).$ Which of the following graphs best represents the resulting curve
A)
B)
C)
D)
Explanation
(b) When we move in the direction of the current in a uniform conductor, the potential difference decreases linearly. When we pass through the cell, from it’s negative to it’s positive terminal, the potential increases by an amount equal to it’s potential difference. This is less than it’s emf, as there is some potential drop across it’s internal resistance when the cell is driving current
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.