Q. The equivalent resistance between the points $P$ and $Q$ in the network given here is equal to (given $r = \frac{3}{2}\Omega$)
A) $\frac{1}{2}\Omega$
B) $1\ \Omega$
C) $\frac{3}{2}\Omega$
D) $2\ \Omega$
Explanation
(b) The given circuit can be simplifies as follows
$R^{'} = \frac{2r}{3} = \frac{2}{3} \times \frac{3}{2} = 1\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.