Q. If the electric current through an electric bulb is 3.2 A, the number of electrons flow through it in one second is
A) $2 \times 10^{9}$
B) $2 \times 10^{19}$
C) $3.2 \times 10^{19}$
D) $1.6 \times 10^{18}$
Explanation
(b) Current $I = \frac{ne}{l}$
$3.2 = \frac{n \times 1.6 \times 10^{- 19}}{1}$
$\ \ \ n = \frac{3.2}{1.6 \times 10^{- 19}} = 2 \times 10^{19}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.