Q. How much current should be passed through acidified water for 100s to liberate 0.224 L of hydrogen?
A) 22.4 A
B) 19.3 A
C) 9.65 A
D) 1 A
Explanation
(b) Hydrogen liberated per sec $= \frac{0.224}{100}Ls^{- 1}.$
In order to liberate 11.2 L of hydrogen per sec charge passed $= 96500\ Cs^{- 1}$
To liberate $= \frac{0.224}{100}Ls^{- 1}$ of hydrogen
$= \frac{96500}{11.2} \times \frac{0.224}{100}$
$= 19.30\ Cs^{- 1} = 19.3A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.