Q. If $400\Omega$ of resistance is made by adding four $100\Omega$ resistance of tolerance 5%, then the tolerance of the combination is
A) 20 %
B) 5 %
C) 10 %
D) 15 %
Explanation
(b) Resistance of combination $R_{e} = 4R$
$\frac{\mathrm{\Delta}R_{e}}{R_{e}} = \frac{\mathrm{\Delta}R}{R}$
$= \frac{5 \times 100}{100} = 5\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.