(c) Applying $\ \ \ \ \ \ \ \ \ \ \ P = \frac{V^{2}}{R}$
$R_{1} = 1\ \Omega,\ R_{2} = 0.5\ \Omega\ and\ R_{3} = 2\ \Omega,\ V_{1} = V_{2} = V_{3} = 3\ volt$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P_{1} = \frac{(3)^{2}}{1} = 9\ W$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P_{2} = \frac{(3)^{2}}{0.5} = 18\ W\ and$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P_{3} = \frac{(3)^{2}}{2} = 4.5\ W$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P_{2} > P_{1} > P_{3}$