Q. Two electroplating cells, one of silver and another of aluminium are connected in series. The ratio of the number of silver atoms to that of aluminium atoms deposited during time $t$ will be
A) 1 : 3
B) 3 : 1
C) 1 : 9
D) 9 : 1
Explanation
(b) No. of ions liberated $(n) = \frac{I \times t}{e \times Valency(p)}$
$ie,\ n \propto \frac{1}{P}$
$\therefore\frac{n_{Ag}}{n_{Al}} = \frac{P_{Al}}{P_{Ag}} = \frac{3}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.