Q. A piece of fuse wire melts when a current of $15\ ampere$ flows through it. With this current, if it dissipates $22.5\ W,\ $the resistance of fuse wire will be
A) Zero
B) $10\ \Omega$
C) $1\ \Omega$
D) $0.10\ \Omega$
Explanation
(d) $P = i^{2}R \Rightarrow 22.5 = (15)^{2} \times R \Rightarrow R = 0.10\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.