Q. In the given circuit, with steady current, the potential drop across the capacitor must be
A) $V$
B) $V/2$
C) $V/3$
D) $2V/3$
Explanation
(c) Moving anticlockwise from $A$
$- iR - V + 2V - 2iR = 0$
or $3iR = V$ or $i = \frac{V}{3R}$
$V_{A} - V_{B} = iR + V - V = iR$
$\Rightarrow$ Potential drop across $C = \frac{V}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.