Q. Calculate the amount of charge flowing in $2\ minutes$ in a wire of resistance $10\Omega$ when a potential difference of $20\ V$ is applied between its ends
A) $120\ C$
B) $240\ C$
C) $20\ C$
D) $4\ C$
Explanation
(b) $i = \frac{V}{R} = \frac{Q}{t} \Rightarrow Q = \frac{Vt}{R} = \frac{20 \times 2 \times 60}{10} = 240C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.