Q. A battery of emf 10V and internal resistance 3$\ \Omega$is connected to an external resistor. The current in the circuit is 0.5A. the terminal voltage of the battery when the circuit is close is
A) 10V
B) Zero
C) 1.5 V
D) 8.5 V
Explanation
(d) Terminal voltage of the battery after closing the circuit is
$V = E\ - \ ir$
=10 - 0.5 × 3
=10 – 1.5= 8.5 V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.