(b) Energy, $E = 1\ kWh = 3.6 \times 10^{6}\ J = QV$ or $\ Q = E/V$ $m = zQ = z\frac{E}{V}$ $\ = \frac{\left( 0.33 \times 10^{- 6} \right)(3.6 \times 10^{6})}{66} = 1.8$ kg.
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