Q.
A heating coil is labelled $100\ W,\ 220\ V.$ The coil is cut in half and the two pieces are joined in parallel to the same source. The energy now liberated per second is
A) $200\ J$
B) $400\ J$
C) $25\ J$
D) $50\ J$
Explanation
(b) When the heating coil is cut into two equal parts and these parts are joined in parallel, the resistance of coil is reduced to one fourth, so power consumed will become 4 times $i.e.\ 400\ Js^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.