(a) Length of wire $= 2\pi r = 2\pi(0.1) = 0.2\pi m$
Resistance of complete wire $= 12 \times 0.2\pi = 2.4\pi\Omega$
$\therefore$ Resistance of each semicircle $= 1.2\pi\Omega$
Hence equivalent resistance $R_{AB} = \frac{1.2\pi}{2} = 0.6\pi\Omega$