Q. Five equal resistors when connected in series dissipated 5 W power. If they are connected in parallel, the power dissipated will be
A) 25 W
B) 50 W
C) 100 W
D) 125 W
Explanation
(d) In series, total resistance of 5 resistance$= 5R$
Power dissipated $= \frac{V^{2}}{5R} = 5$
or $= \frac{V^{2}}{R} = 25$
In parallel, total power $= 5\left( \ \frac{V^{2}}{R} \right) = 5 \times 25 = 125$ W
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.