Q. In the figure given below, the current passing through $6\Omega$ resistor is
A) $0.40\ ampere$
B) $0.48\ ampere$
C) $0.72\ ampere$
D) $0.80\ ampere$
Explanation
(b) P.d. across the circuit $= 1.2 \times \frac{6 \times 4}{6 + 4} = 2.88\ volt$
Current through $6\ ohm$ resistance $= \frac{2.88}{6} = 0.48\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.