Q.
In the circuit shown in the figure, if the potential at point $A$ is taken to be zero, the potential at point $B$ is
A) $- 2V$
B) $+ 1V$
C) $- 1V$
D) $+ 2V$
Explanation
(b) Current from $D$ to $C = 1A$
$\therefore V_{D} - V_{C} = 2 \times 1 = 2V$
$V_{A} = 0\ \therefore V_{C} = 1V,\ \therefore V_{D} - V_{C} = 2$
$\Rightarrow V_{D} - 1 = 2\ \therefore V_{D} = 3V$
$\therefore V_{D} - V_{B} = 2\therefore 3 - V_{B} = 2\therefore V_{B} = 1V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.