Q. Five equal resistances, each of resistance $R,$are connected as shown in figure below. A bettery of $V$ volt is connected between $A\ and\ B.$ The current flowing in $FC$ will be
A) $\frac{3V}{R}$
B) $\frac{V}{R}$
C) $\frac{V}{2R}$
D) $\frac{2V}{R}$
Explanation
(c) $I = \frac{V}{R}$
$\therefore\ Current\ in\ FC = \frac{1}{2} = \frac{V}{2R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.