Q. Three resistance $A,B$ and $C$ have values $3R,\ 6R$ and $R$ respectively. When some potential difference is applied across the network, the thermal powers dissipated by $A,B$ and $C$ are in the ratio

A) 2 :3 :4
B) 2 :4 :3
C) 4 :2 :3
D) 3 :2 :4
Explanation

(c) Thermal power in$\ A = P_{A} = \left( \frac{2i}{3} \right)^{2}3R = \frac{4}{3}i^{2}R$
Thermal power in$\ B = P_{B} = \left( \frac{i}{3} \right)^{2}6R = \frac{2}{3}i^{2}R$
Thermal power in
$C = P_{C} = i^{2}R$
$\Rightarrow P_{A}:P_{B}:P_{C}$
$= \frac{4}{3}\ :\frac{2}{3}\ :1 = 4\ :2\ :3$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.