Q. In the circuit given, the current relation to a balanced Wheatstone’s bridge is
A) $\frac{P}{Q} = \frac{R}{S}$
B) $\frac{P}{Q} = \frac{S}{R}$
C) $\frac{P}{S} = \frac{Q}{R}$
D) $\frac{P}{R} = \frac{S}{Q}$
Explanation
(d) For balanced Wheatstone bridge
$\ \ \ \ \ \ \frac{P}{R} = \frac{S}{Q}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.