Q. Thomson coefficient of a conductor is $10\mu V/K.$ The two ends of it are kept at $50℃$ and $60℃$ respectively. Amount of heat absorbed by the conductor when a charge of $10C$ flows through it is
A) $1000\ J$
B) $100\ J$
C) $100\ mJ$
D) $1\ mJ$
Explanation
(d) By using $H = \sigma Q\mathrm{\Delta}\theta$
$\Rightarrow H = \left( 10 \times 10^{- 6} \right) \times 10 \times (60 - 50) = 10^{- 3}J = 1\ mJ$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.