Q. A small power station supplies electricity to 5000 lamps connected in parallel. Each lamp has a resistance of 220 and is operated at 220 V. The total current supplied by the station is
A) 2500 A
B) 3500 A
C) 5000 A
D) 10000 A
Explanation
(c) As resistances are in parallel
$\frac{1}{R_{eq}} = \frac{1}{220} + \frac{1}{220} + \ \ldots 5000\ times$
$\frac{1}{R_{eq}} = \frac{5000}{220}$
$R_{eq} = \frac{220}{5000}$
$\ \ \ \ \ I = \frac{220}{\frac{220}{5000}}$
$\ \ \ \ \ I = 5000\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.