Q. A meter bridge is set-up as shown in figure, to determine an unknown resistance X using a standard 10$\ \Omega\ $resistor. The galvanometer shows null point when tapping key is at 52cm mark. The end-corrections are 1cm and 2cm respectively for the ends A and B. the determined value of x is
A) 10.2$\ \Omega$
B) 10.6$\ \Omega$
C) 10.8$\ \Omega$
D) 11.1$\ \Omega$
Explanation
(b) Using the concept of balanced wheat stone bridge, we have
$\ \ \ \ \ \ \ \ \ \ \frac{P}{Q} = \frac{R}{S}$
$\frac{x}{52 + 1} = \frac{10}{48 + 2}$
$\ \ \ \ \ \ \ \ \ \ \ x = \frac{10 \times 53}{50}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ = 10.6\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.