Q. To deposit one litre of hydrogen at $22.4$ atmosphere from acidulated water, the quantity of electricity that must pass through is
A) $1\ coulomb$
B) $22.4\ coulomb$
C) $96500\ coulomb$
D) $193000\ coulomb$
Explanation
(d) $V_{2} = \frac{22.4 \times 1}{1} = 22.4\ litre\ $at NTP
$\because 11.2\ litre$ of$\ H_{2}$ is liberated by $96,500\ C$
$\therefore 22.4\ litre\ $of$\ H_{2}$ is liberated by $96500 \times 2 = 1,93,000\ C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.