Q. In a circuit 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is $G$ then value of the shunt is
A) $19\ G$
B) $20\ G$
C) $\frac{G}{20}$
D) $\frac{G}{19}$
Explanation
(d) $\frac{i_{g}}{i} = \frac{S}{G + S\ } \Rightarrow \frac{5}{100} = \frac{S}{G + S} \Rightarrow S = \frac{G}{19}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.