Q. Potential difference between the points $P$ and $Q$ in the electric circuit shown is
A) $4.5\ V$
B) $1.2\ V$
C) $2.4\ V$
D) $2.88\ V$
Explanation
(d) Equivalent resistance between $P$ and $Q$
$\frac{1}{R_{PQ}} = \frac{1}{(6 + 2)} + \frac{1}{3} + \frac{1}{(4 + 12)} \Rightarrow R_{PQ} = \frac{48}{25}\Omega$
Current between $P$ and $Q;i = 1.5A$
So, potential difference between $P$ and $Q$
$V_{PQ} = 1.5 \times \frac{48}{25} = 2.88V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.