Q. The masses of the three wires of copper are in the ratio 5 : 3 : 1 and their lengths are in the ratio 1 : 3 : 5 the ratio of their electrical resistance is

A) 5 : 3 : 1
B) $\sqrt{125}\ :15\ :1$
C) 1 : 15 : 125
D) 1 : 3 : 5
Explanation

(c) Given, $l_{1} = 1K,\ l_{2} = 3K,l_{3} = 5K$
or ${\ \ \ \ m}_{1} = 5m,m_{2} = 3m,m_{3} = 1m$
We knows
$R = \frac{\rho l}{A}$
So $R_{1}:R_{2}:R_{3} = \frac{l_{1}}{A_{1}}\ :\frac{l_{2}}{A_{2}}\ :\frac{l_{3}}{A_{3}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{l_{1}^{2}}{V_{1}}\ :\frac{l_{2}^{2}}{V_{2}}\ :\frac{l_{3}^{2}}{V_{3}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{l_{1}^{2}}{m_{1}}\ :\frac{l_{2}^{2}}{m_{2}}\ :\frac{l_{3}^{2}}{m_{3}}$
$\ \ \ \ \ \ \ \ \ \ = \frac{1}{5}\ :\frac{9}{3}\ :\frac{25}{1} = 1\ :15\ :125$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.