Q. A metallic wire of resistance 12$\ \Omega$ is bent to from a square. The resistance between two diagonal points would be
A) 12$\ \Omega$
B) 24$\ \Omega$
C) 6$\ \Omega$
D) 3$\ \Omega$
Explanation
(d) Given, the resistance of wire R=12$\Omega$. The wire is bent in square form
$R_{1} = 3 + 3 = 6\Omega$
$R_{2} = 3 + 3 = 6\Omega$
$\frac{1}{R^{''}} = \frac{1}{6} + \frac{1}{6}$
$or\ \ \frac{1}{R^{''}} = \frac{2}{6}$
$or\ \ \ R^{''} = 3\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.