Q. On passing 96500 $coulomb$ of charge through a solution $CuSO_{4}$ the amount of copper liberated is
A) $64\ gm$
B) $32\ gm$
C) $32\ kg$
D) $64\ kg$
Explanation
(b) 1 faraday (96500$C$) is the electricity which liberates that amount of substance which is equal to equivalent wt
So liberated amount of$\ Cu\ $is$\ \frac{63.5}{2}$
$= 31.25\ gm \approx 32\ gm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.