Resistors $P$ and $Q$ are connected in the gaps of the meter bridge. The balancing point is obtained $\frac{1}{3}m$ from the zero end. If a 6$\ \Omega$ resistance is connected in series with $P$ the balance point shifts to $\frac{2}{3}m$ from the same end. $P$ and $Q$ are

Question

Dr. Abubacker · Accepted Answer

(b) $\frac{P}{Q} = \frac{1/3}{1 - 1/3} = \frac{1/3}{2/3}$
$\Longrightarrow P:Q = 1:2\ $
$P = k,\ \ Q = 2k$
$\frac{P + 6}{Q} = \frac{\frac{2}{3}}{1 - \frac{2}{3}}$
$\Longrightarrow \frac{P + 6}{Q} = \frac{2}{1}$
$\frac{k + 6}{2k} = \frac{2}{1}$
$\Longrightarrow k + 6 = 4k$
$\Longrightarrow k = 2$
$	herefore\ \ P = 2\Omega,\ Q = 4\Omega$

Q. Resistors $P$ and $Q$ are connected in the gaps of the meter bridge. The balancing point is obtained $\frac{1}{3}m$ from the zero end. If a 6$\ \Omega$ resistance is connected in series with $P$ the balance point shifts to $\frac{2}{3}m$ from the same end. $P$ and $Q$ are

Explanation

Reviewed by Dr. Abubacker

Want more practice?