Q. Seven resistance are connected as shown in the figure. The equivalent resistance between $A$ and $B$ is
A) $3\ \Omega$
B) $4\ \Omega$
C) $4.5\ \Omega$
D) $5\ \Omega$
Explanation
(b) The given circuit can be simplified as follows
Now it is a balanced Wheatstone bridge
So,
$\Rightarrow R_{AB} = \frac{8 \times 8}{8 + 8} = \frac{64}{16} = 4\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.