(c) In series combination of cells current, $i = \frac{nE}{nr + R}$
In parallel combination of cell, $i^{'} = \frac{E}{(\frac{r}{n) + R}}$
If $i = i^{'}\ then\ \frac{nE}{nr + R} = \frac{E}{(\frac{r}{n) + R}} = \frac{nE}{r + nR}$
It will be so if $r = R$