Q. The resistance of $1\ A$ ammeter is $0.018\Omega.$ To convert it into $10\ A$ ammeter, the shunt resistance required will be
A) $0.18\ \Omega$
B) $0.0018\ \Omega$
C) $0.002\ \Omega$
D) $0.12\ \Omega$
Explanation
(c) $S = \frac{i_{g}G}{(i - i_{g})} = \frac{1 \times 0.018}{10 - 1} = \frac{0.018}{9} = 0.002\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.