Q.
A 100 W bulb $B_{1}$ and two 60 W bulb $B_{2}\ and\ B_{3}$ are connected to a 250 V source as shown in the figure. Now $W_{1},W_{2}\ and\ W_{3}$ are the out-put powers of the bulbs $B_{1},\ B_{2}\ and\ B_{3}$ respectively. Then
A) $W_{1} >$ $W_{2} = \ W_{3}$
B) $W_{1} >$ $W_{2} > \ W_{3}$
C) $W_{1} <$ $W_{2} = \ W_{3}$
D) $W_{1} <$ $W_{2} < \ W_{3}$
Explanation
(d) Voltage across $B_{3}$ is greatest hence $B_{3}$ will show maximum brightness. In series combination of bulbs, the bulb of lesser wattage will glow more bright. Hence $W_{2} > W_{1}$.
So , $W_{1} < W_{2} < W_{3}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.