Q. Resistors of $1,\ 2,\ 3\ ohm$ are connected in the form of a triangle. If a 1.5 volt cell of negligible internal resistance is connected across $3\ ohm$ resistor, the current flowing through this resistance will be
A) $0.25\ amp$
B) $0.5\ amp$
C) $1.0\ amp$
D) $1.5\ amp$
Explanation
(b) $i_{1} + i_{2} = \frac{1.5}{3/2} = 1\ amp$
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$\frac{i_{1}}{i_{2}} = \frac{3}{3} \Rightarrow i_{1} = i_{2}\ \therefore i_{2} = 0.5A = i_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.