Q. In a neon gas discharge tube $Ne^{+}$ions moving through a cross-section of the tube each second to the right is $2.9 \times 10^{18},$ while $1.2 \times 10^{18}$ electron move towards left in the same time; the electronic charge being $1.6 \times 10^{- 19}C$, the net electric current is

A) 0.27 A to the right
B) 0.66 A to the right
C) 0.66 A to the left
D) Zero
Explanation

(b) Current, $i = (2.9 \times 10^{18} + 1.2 \times 10^{18}) \times 1.6 \times 10^{- 19}$
$= 0.66\ A$ towards right

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.