If a wire of resistance $20\Omega$ is covered with ice and a voltage of $210\ V$ is applied across the wire, then the rate of melting of ice is

Question

Dr. Abubacker · Accepted Answer

(c) $H = \frac{V^{2}}{R} 	imes t = \frac{(210)^{2}}{20} 	imes 1 = mL$
$	herefore\frac{(210)^{2}}{20} = m 	imes 80 	imes 4.2 \Rightarrow m = 6.56\ g/s$

Q. If a wire of resistance $20\Omega$ is covered with ice and a voltage of $210\ V$ is applied across the wire, then the rate of melting of ice is

Explanation

Reviewed by Dr. Abubacker

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