Q. Two resistances $R\ and\ 2R$ are connected in parallel in an electric circuit. The thermal energy developed in in $R\ and\ 2R$ is in the ratio
A) 1 : 2
B) 1 : 4
C) 4 : 1
D) 2 : 1
Explanation
(d) The resistance are connected in parallel hence, voltage will remain constant
$E = \frac{V^{2}t}{R}$
$\Longrightarrow E \propto \frac{1}{R}$
$\frac{E_{1}}{E_{2}} = \frac{R_{2}}{R_{1}} = \frac{2R}{R} = \frac{2}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.