(a) $\frac{R_{1}}{R_{2}} = \frac{P_{2}}{P_{1}} = \frac{100}{40} = \frac{5}{2}.$ Resistance of $40\ W$ bulb is $\frac{5}{2}$ times than $100\ W.$ In series, $P = i^{2}R$ and in parallel, $P = \frac{V^{2}}{R}.$ So $40\ W$ in series and $100\ W$ in parallel will glow brighter