A current of $6A$ enters one corner $P$ of an equilateral triangle $PQR$ having 3 wires of resistances $2\Omega$ each and leaves by the corner $R.$ Then the current $I_{1}$ and $I_{2}$ are [image:3_image40.emf]

Question

Dr. Abubacker · Accepted Answer

(a) $I_{1} = \frac{2}{2 + 4} 	imes 6 = 2A$
$I_{2} = 4\ amp$

Q. A current of $6A$ enters one corner $P$ of an equilateral triangle $PQR$ having 3 wires of resistances $2\Omega$ each and leaves by the corner $R.$ Then the current $I_{1}$ and $I_{2}$ are

Explanation

Reviewed by Dr. Abubacker

Want more practice?