Q. In a galvanometer 5% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, the shunt resistance S connected to the galvanometer is
A) 19G
B) G/19
C) 20G
D) G/20
Explanation
(b) Shunt of an ammeter,
$S = \frac{I_{g} \times G}{I - I_{g}}$
$\ \ \ = \frac{5 \times G}{100 - 5} = \frac{G}{19}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.