The current $i_{1}$and $i_{2}$through the resistor $R_{1}( = 10\Omega)$and $R_{2}( = 30\Omega)$in the circuit diagram with $E_{1} = 3V,E_{2} = 3\ and\ E_{3} = 2V$are respectively.

Question

Dr. Abubacker · Accepted Answer

(a) In closed loop EFGDE
$i_{2}R_{2} = E_{2}$
$i_{2} 	imes 30 = 3$
$i_{2} = 0.1A$
In closed loop ABCEA
$- i_{1}R_{1} - E_{1} + E_{2} + E_{3} = 0$
$- i_{1} 	imes 10 - 3 + 3 + 2 = 0$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ i_{1} = 0.2A$

Q. The current $i_{1}$and $i_{2}$through the resistor $R_{1}( = 10\Omega)$and $R_{2}( = 30\Omega)$in the circuit diagram with $E_{1} = 3V,E_{2} = 3\ and\ E_{3} = 2V$are respectively.

Explanation

Reviewed by Dr. Abubacker

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