Q. The resistance between the terminal points $A$ and $B$ of the given infinitely long circuit will be
A) $(\sqrt{3} - 1)$
B) $(1 - \sqrt{3})$
C) $(1 + \sqrt{3})$
D) $(2 + \sqrt{3})$
Explanation
(c) Let equivalent resistance between $A$ and $B$ be $R,$ then equivalent resistance between $C$ and $D$ will also be $R$
$R^{'} = \frac{R}{R + 1} + 2 = R$
$\Rightarrow R^{2} - 2R - 2 = 0$
$\therefore R = \frac{2 \pm \sqrt{4 + 8}}{2} = \sqrt{3} + 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.