Q. Figure shows a network of three resistance. When some potential difference is applied across the network, the thermal powers dissipated by $A$,$B\ and\ C$ in the ratio

A) 2 : 3 : 4
B) 2 : 4 : 3
C) 4 : 2 : 3
D) 3 : 2 : 4
Explanation

(c) Let current flow from $b$ to $a$ as shown
[image:3_image153.emf]
Ratio of thermal power is $\left( \ \frac{2}{3}I \right)^{2}3R\ :\left( \ \frac{1}{3}I \right)^{2}6R\ :I^{2}R$
or $\frac{4}{3}:\frac{2}{3}:1$ or 4 : 2 : 3.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.